x^4/3+4x^2/3-32=0

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Solution for x^4/3+4x^2/3-32=0 equation: 


x in (-oo:+oo)

(x^4)/3+(4*x^2)/3-32 = 0

1/3*x^4+4/3*x^2-32 = 0

t_1 = x^2

1/3*t_1^2+4/3*t_1^1-32 = 0

1/3*t_1^2+4/3*t_1-32 = 0

DELTA = (4/3)^2-(-32*1/3*4)

DELTA = 400/9

DELTA > 0

t_1 = ((400/9)^(1/2)-4/3)/(1/3*2) or t_1 = (-(400/9)^(1/2)-4/3)/(1/3*2)

t_1 = 8 or t_1 = -12

t_1 = -12

x^2+12 = 0

1*x^2 = -12 // : 1

x^2 = -12

t_1 = 8

x^2-8 = 0

1*x^2 = 8 // : 1

x^2 = 8

x^2 = 8 // ^ 1/2

abs(x) = 2*2^(1/2)

x = 2*2^(1/2) or x = -(2*2^(1/2))

x in { 2*2^(1/2), -(2*2^(1/2)) }

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